Integrand size = 22, antiderivative size = 94 \[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=-\frac {b (b c-2 a d) x^{1+m}}{d^2 (1+m)}+\frac {b^2 x^{3+m}}{d (3+m)}+\frac {(b c-a d)^2 x^{1+m} \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},-\frac {d x^2}{c}\right )}{c d^2 (1+m)} \]
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Time = 0.05 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {472, 371} \[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=\frac {x^{m+1} (b c-a d)^2 \operatorname {Hypergeometric2F1}\left (1,\frac {m+1}{2},\frac {m+3}{2},-\frac {d x^2}{c}\right )}{c d^2 (m+1)}-\frac {b x^{m+1} (b c-2 a d)}{d^2 (m+1)}+\frac {b^2 x^{m+3}}{d (m+3)} \]
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Rule 371
Rule 472
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {b (b c-2 a d) x^m}{d^2}+\frac {b^2 x^{2+m}}{d}+\frac {\left (b^2 c^2-2 a b c d+a^2 d^2\right ) x^m}{d^2 \left (c+d x^2\right )}\right ) \, dx \\ & = -\frac {b (b c-2 a d) x^{1+m}}{d^2 (1+m)}+\frac {b^2 x^{3+m}}{d (3+m)}+\frac {(b c-a d)^2 \int \frac {x^m}{c+d x^2} \, dx}{d^2} \\ & = -\frac {b (b c-2 a d) x^{1+m}}{d^2 (1+m)}+\frac {b^2 x^{3+m}}{d (3+m)}+\frac {(b c-a d)^2 x^{1+m} \, _2F_1\left (1,\frac {1+m}{2};\frac {3+m}{2};-\frac {d x^2}{c}\right )}{c d^2 (1+m)} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 118, normalized size of antiderivative = 1.26 \[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=\frac {x^{1+m} \left (\frac {a^2 \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},-\frac {d x^2}{c}\right )}{1+m}+b x^2 \left (\frac {2 a \operatorname {Hypergeometric2F1}\left (1,\frac {3+m}{2},\frac {5+m}{2},-\frac {d x^2}{c}\right )}{3+m}+\frac {b x^2 \operatorname {Hypergeometric2F1}\left (1,\frac {5+m}{2},\frac {7+m}{2},-\frac {d x^2}{c}\right )}{5+m}\right )\right )}{c} \]
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\[\int \frac {x^{m} \left (b \,x^{2}+a \right )^{2}}{d \,x^{2}+c}d x\]
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\[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{2} x^{m}}{d x^{2} + c} \,d x } \]
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Result contains complex when optimal does not.
Time = 2.99 (sec) , antiderivative size = 292, normalized size of antiderivative = 3.11 \[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=\frac {a^{2} m x^{m + 1} \Phi \left (\frac {d x^{2} e^{i \pi }}{c}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{4 c \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {a^{2} x^{m + 1} \Phi \left (\frac {d x^{2} e^{i \pi }}{c}, 1, \frac {m}{2} + \frac {1}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {1}{2}\right )}{4 c \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )} + \frac {a b m x^{m + 3} \Phi \left (\frac {d x^{2} e^{i \pi }}{c}, 1, \frac {m}{2} + \frac {3}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )}{2 c \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} + \frac {3 a b x^{m + 3} \Phi \left (\frac {d x^{2} e^{i \pi }}{c}, 1, \frac {m}{2} + \frac {3}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {3}{2}\right )}{2 c \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )} + \frac {b^{2} m x^{m + 5} \Phi \left (\frac {d x^{2} e^{i \pi }}{c}, 1, \frac {m}{2} + \frac {5}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )}{4 c \Gamma \left (\frac {m}{2} + \frac {7}{2}\right )} + \frac {5 b^{2} x^{m + 5} \Phi \left (\frac {d x^{2} e^{i \pi }}{c}, 1, \frac {m}{2} + \frac {5}{2}\right ) \Gamma \left (\frac {m}{2} + \frac {5}{2}\right )}{4 c \Gamma \left (\frac {m}{2} + \frac {7}{2}\right )} \]
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\[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{2} x^{m}}{d x^{2} + c} \,d x } \]
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\[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{2} x^{m}}{d x^{2} + c} \,d x } \]
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Timed out. \[ \int \frac {x^m \left (a+b x^2\right )^2}{c+d x^2} \, dx=\int \frac {x^m\,{\left (b\,x^2+a\right )}^2}{d\,x^2+c} \,d x \]
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